DRL-4s

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mama6600

I’m trying to write a DRL-4s program but i got stuck from the reset timer and reward. Would anyone have suggestion for that?

[Med_Support]

Gary Bamberger

Hello,

It is very hard to make a suggestion without seeing the code that you have written.  Here is a possibility that might work for you:

S.S.2,
S1,
#START: ---> S2

S2,
4#R1: ---> S2            \ If we receive 4 responses before the timer runs out, restart the timer
4": ON ^Pellet ---> S3  \ If 4s passes with less than 4 responses, issue reinforcement

S3,
0.05": OFF ^Pellet ---> S2

[Med_Support]

mama6600

S.S.2, \reset timer

S1,
#R^Leftlever: SET T = 0; Z2 ---> S2

S2,
0.01": SET T = T +0.1 ---> SX

S.S.3, \If lever press occur at or passes over 4s, it will gain reward. If lever press occur before 4s, the lever press will reset the time to zero

S1,
#R^leftlever: IF T >= 4 (@True, @False)
@Ture: ON ^Reward ---> S2
@False: Z2 ---> SX

S2,
4" : OFF ^Reward ---> SX

 

The problem is how to write a script which is describing: “If lever press occur at or passes over 4s, gain reward. If every single lever press occur before 4s (0s-3.9s), the certain lever press will reset the time to zero”.

[Med_Support]

Gary Bamberger

It looks like my original code was very close. I think this might do what you want:

S.S.2,
S1,
  #START: ---> S2

S2,
  #R^LeftLever: ---> S2  \ If we receive a responses before the timer runs out, restart the timer
  3.99":        ---> S3  \ If 3.99s passes, then reward the next lever press

S3,
  #R^LeftLever: ON ^Reward ---> S4  \ 3.99 + 0.01 = 4.00s  so any response will be at 4s or later

S4,
  4": OFF ^Reward ---> S2  \ After reward go back for the next 4s interval

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