any way to get the state of a lever?

[Med_Support]

mikediamond45

Hello,
I am using MedPC & I would like to know if there is any way to get the current state of a lever?
That is, I would like to know how long a mouse depresses a lever?

For example, I will only give reward if the mouse presses the lever for >= 5 seconds.
^Lever = 1
^Reward = 2

S.S.1,
S1,
0.01": SET M = 0 ---> S2
S2,
#R^Lever: ADD M; SHOW 1, Counter, M;
If (M >= 5) AND (output state of ^Lever = pressed) [@True, @False]
@True: ON ^Reward ---> S3
@False: ---> SX
S3,
1": OFF ^Reward; SET M = 0 ---> S2

Is there any code that I can substitute for (output state of ^Lever = pressed) ?

[Med_Support]

Gary Bamberger

The following code sample should help:

\***************************************************
\ BEAM BREAK DEFINED - 20ms BREAK, 20ms RELEASE
\***************************************************
S.S.2, \ Beam Break Defined - 20ms Break, 20ms Release.
S1, \ Inputs in Level Mode generate an input "count" on each
\ interrupt. With a 10 ms system resolution 2 counts
\ will be reached in 20 ms. The Z3 pulse is used to
\ signal a completed Beam Break. The second statement resets
\ the counter every 20 ms so that a partial Beam Break of
\ less than 20 ms will not constitute a Response.
#R1: ADD Y; IF Y >= 2 [@BeamBreak, @NoBeamBreak]
@Break: Z3; SET Y = 0 ---> S2
@NoBreak: ---> SX
0.02": SET Y = 0 ---> S1

S2, \ As long as the Beam is broken the second statement
\ causes a re-entry to this State. This resets the
\ the internal 20 ms timer so it never times out. When
\ the Beam is released for 20 ms the timer times out
\ and a Z4 pulse signals the release.
0.02": Z4 ---> S1
#R1: ---> S2

The code was for input beams, but it will also work for levers in level mode. All you need to do is time the length between each Z-pulse. If it is greater than 5s, issue the reward.
Gary

[Med_Support]

mikediamond45

yep, changing it to level mode & modifying the code worked, thx.

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